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18=r^2
We move all terms to the left:
18-(r^2)=0
We add all the numbers together, and all the variables
-1r^2+18=0
a = -1; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·(-1)·18
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{2}}{2*-1}=\frac{0-6\sqrt{2}}{-2} =-\frac{6\sqrt{2}}{-2} =-\frac{3\sqrt{2}}{-1} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{2}}{2*-1}=\frac{0+6\sqrt{2}}{-2} =\frac{6\sqrt{2}}{-2} =\frac{3\sqrt{2}}{-1} $
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